A block is sliding on a rough horizontal surface. If the contact force on the block is √2 times the the frictional force,the frictional force is
Answers
Answered by
55
let coefficient of friction be x
contact force =√(f^2+N^2)
√(f^2+N^2)=√2f
S.O.B.S
f^2+N^2=2f^2
N^2=2f^2-f^2
N^2=f^2
N^2=x^2.N^2 (f=x.N)
x^2=1
x=1
coefficient of friction=1
HOPE YOU UNDERSTAND IT.
contact force =√(f^2+N^2)
√(f^2+N^2)=√2f
S.O.B.S
f^2+N^2=2f^2
N^2=2f^2-f^2
N^2=f^2
N^2=x^2.N^2 (f=x.N)
x^2=1
x=1
coefficient of friction=1
HOPE YOU UNDERSTAND IT.
Similar questions