Question

A block is sliding on a rough horizontal surface. If the the contact force on the block √2 is times the frictional force is ?​

Answer 1

Explanation:

Let coefficient of friction be x

contact force =√(f^2+N^2)

√(f^2+N^2)=√2f

S.O.B.S

f^2+N^2=2f^2     

N^2=2f^2-f^2

N^2=f^2

N^2=x^2.N^2          (f=x.N)

x^2=1

x=1

coefficient of friction=1

 HOPE YOU UNDERSTAND IT.

Answer 2

Answer:

0.25

12–√

2–√

1

Answer :

D

Solution :

R=N2+f2−−−−−−−√,N=mg

Explanation:

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