A block is sliding on a rough horizontal surface. If the the contact force on the block √2 is times the frictional force is ?
Answers
Answered by
3
Explanation:
Let coefficient of friction be x
contact force =√(f^2+N^2)
√(f^2+N^2)=√2f
S.O.B.S
f^2+N^2=2f^2
N^2=2f^2-f^2
N^2=f^2
N^2=x^2.N^2 (f=x.N)
x^2=1
x=1
coefficient of friction=1
HOPE YOU UNDERSTAND IT.
Answered by
0
Answer:
0.25
12–√
2–√
1
Answer :
D
Solution :
R=N2+f2−−−−−−−√,N=mg
Explanation:
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