A block is weighing 1kg is in the shape of a cube of length 10cm .It is kept on a horizontal table .Find the pressure on the portion of the table where the block is kept.
Answers
Answered by
60
Pressure = Force / Area
= mg / A
= (1 kg × 9.8 m/s²) / (0.1 m × 0.1 m)
= 980 pascals
∴ Pressure acting on the table by block is 980 pascals
[Note: If g = 10 m/s² then pressure will be 1 kilo pascals]
= mg / A
= (1 kg × 9.8 m/s²) / (0.1 m × 0.1 m)
= 980 pascals
∴ Pressure acting on the table by block is 980 pascals
[Note: If g = 10 m/s² then pressure will be 1 kilo pascals]
Answered by
3
Area of the surface = 10cm × 10cm = 100cm²
100cm² into m² = 100/100×100 = 0.01m²
F = mg
(The exact value of g is 9.8 but for the easy calculation we take g as 10 which is approximate value)
Taking g as 9.8 -
F = 1× 9.8
F = 9.8
Now,
Pressure = Fore / Area
P = 9.8 / 0.01 = 980 Pa
Taking g as 10 -
F = 1 × 10
F = 10
Now,
Pressure = Force / Area
P = 10 / 0.01 = 1000Pa
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