Question

a block mass 0.2 kg is suspended from the ceiling by a light string. A second block of mass 0.3 kg is suspended from the first block through another string. Find the tensions in the two strings. Take g = 10 m/s²

Answer 1

let block m1=0.2

block m2=0.3

m2g-T=m2a

T-m1g=m1a

adding the above two equations

m2g-m1g=a(m1+m2)

g(0.3-0.2)=a(0.3+0.2)

g*0.1=0.5*a

10/5=a

a=2

hope it helps and plz mark as brainliest

Answer 2

Answer:

The tensions in the two strings are 5 N and 3 N, respectively.

Explanation:

The free-body diagrams for both the blocks are given in the attachment

Given :

From the free-body diagram of the 0.3 kg block,

mass=m=0.3kg

g=10m/s²

T = 0.3g

⇒ T= 0.3 × 10 = 3 N

Now, from the free-body diagram of the 0.2 kg block,

T1 = 0.2g + T

⇒ T1= 0.2 × 10 + 3 = 5 N

∴ The tensions in the two strings are 5 N and 3 N, respectively.