A block mass 20kg is lying on an inclinedplane of angle 30°
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Answered by
5
Answer:To keep the block at rest ,
F min =mg ( sin60° -uk cos 60° ). = 200( 1/2) (√3-u ) =100(√3-u)
There fore force required to keep the block at rest is 100( √3-u)
Explanation:
Answered by
0
Answer:
Very easy. Just let it be there.
Explanation:
The block is not disturbing you, let it have some quiet time.
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