A block measures 20cm by 10cm by 5cm. Determine the minimum pressure the solid can exert on a flat surface if the mass is 50kg
Answers
Given data : A block measures 20cm by 10cm by 5cm and mass of block is 50 kg.
To find : Determine the minimum pressure the solid block can exert on a flat surface.
Solution : As per given data we know that shape of solid block is cuboid. Here we know, opposite site faces of cuboid are equal.
Let, diamension's of solid block as follows :
- Length of block = 20 cm
- Width of block = 10 cm
- Height of block = 5 cm
- Mass of block = 50 kg
Here, we know block is placed on flat surface, hence to calculate force exerted by block on flat surface we use formula of force,
⟹ Force = mass * acceleration due to gravity
⟹ Force = 50 * 9.8
⟹ Force = 490 N
We can place the solid block in 3 ways so,
Now, we use formula of pressure,
⟹ Pressure = Force/Area
⟹ Pressure = 490/(length * width)
⟹ Pressure = 490/(20 * 10)
⟹ Pressure = 490/200
⟹ Pressure = 2.45 pa ----{1}
⟹ Pressure = Force/Area
⟹ Pressure = 490/(length * height)
⟹ Pressure = 490/(20 * 5)
⟹ Pressure = 490/100
⟹ Pressure = 4.9 pa ----{2}
⟹ Pressure = Force/Area
⟹ Pressure = 490/(width * height)
⟹ Pressure = 490/(10 * 5)
⟹ Pressure = 490/50
⟹ Pressure = 9.8 pa ----{3}
Answer : Hence, from {1}, {2} and {3} maximum pressure is 9.8 pa and minimum pressure is 2.45 pa.
[ 2.45 pa < 4.9 pa < 9.8 pa]