Physics, asked by Anonymous, 9 months ago

A block measuring 20cm by 10cm by 4cm rests on a flat surface. The block has a weight of 6N. Determine: The minimum pressure it exerts on the surface. The density of the block in kg/m3

Answers

Answered by Anonymous
7

Answer:

Explanation:

WE know volume of block in cm^{3}=l×b×h=20×10×4=800cm^{3}

and now mass(m)=6/10=600gm

therefore density(ρ)=0.75gm/cm³

and pressure is FORCE/AREA=6x100/20x10=3pascal

Answered by Anonymous
0

Answer:

Explanation:

WE know volume of block in =l×b×h=20×10×4=800and now mass(m)=6/10=600gmtherefore density(ρ)=0.75gm/cm³and pressure is FORCE/AREA=6x100/20x10=3pascal

Similar questions