A block measuring 20cm by 10cm by 5cm rests on a flat surface. The block has a weight of 3N. Determine the maximum pressure it exerts on the surface
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Answer:
0.06 Pa
Explanation:
P =F÷A
Max pressure = Force ÷minimum area
Force = weight = 3N
Min area =10×5 = 50cm²
3÷50 = 0.06 Pa
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