Physics, asked by danushkkk, 11 months ago

A block moves from A to B in two equal time
intervals with velocity 10 m/s and 20 m/s
respectively. The magnitude of average velocity from
A to B will be
10 m/s
qui
20 mis
(1) 40 m/s
(3) 6 m/s
(2) 15 m/s
(4) 10 m/s​

Answers

Answered by sashika
15

Answer:

15m/s

Explanation:

avg velocity=(Va+Vb)/2

=(10+20)/2

=15m/s

cheers...❤❤❤

Answered by Raghul190602
4

Answer:

Body with equal time intervals then average velocity formula is v1+v2/2

  • so 10+20/2
  • 30/2
  • 15m/s
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