Question

A block moves from A to B in two equal time
intervals with velocity 10 m/s and 20 m/s
respectively. The magnitude of average velocity from
A to will be (Neglect size of block)
10 m/s
20 m/s
(1) 40 mis
(2) 15 m/s
(4) 10 m/s
15 ms
By Guy! 4
(3) 6 m/s​

Answer 1

Hey Dear,

◆ Answer - (2)

vavg = 15 m/s

● Explaination -

Let t be the equal time interval for A to B as well as B to A.

For A to B -

s1 = v1.t

s1 = 10t

For B to A -

s2 = v2.t

s2 = 20t

Average velocity of the block will be -

vavg = (s1 + s2) / (t + t)

vavg = (10t + 20t) / 2t

vavg = 15 m/s

Therefore, average velocity of the block will be 15 m/s.

Thanks dear...