A block moving with speed of 20 m/s comes to rest after 4 sec. If mass of block is 2 kg. Find resistive force acting on the block.
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Answer:
given, u = 20m/sec, t = 4 sec, m = 2 kg , v = 0
to find retarding force
f = m×a
we know mass but we have to find the acceleration
a = (v - u)/t
=> (0 - 20)/4
=> -5 m/sec^2
therefore retarding force f = 2 × (-5)
=> hence f = -10 N
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