Question

a block of 10 kg mass is placed on rough inclined surface as shown in figure. The acceleration of the block will be...
ans is 0....how???

Answer 1

Dear student,
Block B together with block A is lying on rough surface with coefficient of friction=0.5.
So, it will be able to accelerate if force applied is greater than (coefficient of friction)*(mA+mB)*g=0.5*10*10=50 N.
But force applied is only 25 N which is less than 50 N.
So there will be no acceleration and frictional force between A and B wont arise.
So frictional force= 0 [Ans]
Regards,

Answer 2

Find the value of frictional force

=uN (where N= mgcostheta)

=10g√3/2

.

.

Now find accelerating force in downward direction

=mgsintheta

=10g/2

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.it is clear thst frictional force is more than acc. Force that is tje reason that the block wont move

.

And thus acc. Is 0