Question

a block of 100n is kept on a rough horizontal surface when a force of 60 n is applied on the block it just begins to move while a force of 40n is required to move it with a constant speed. then​

Answer 1

Answer:

1003–√N

1003–√N

503–√N

50N

Answer :

D

Solution :

F=μsmgμ2s+1−−−−−√

Explanation:

Answer 2

Complete question:

A block of weight 100 N is kept on a rough horizontal table. When a force of 60 N is applied on the block, it just begins to move while a force of 40 N is required to move it with a constant speed. Then

(1) Maximum static friction is 40 N

(2) Sliding friction is 60 N

(3) Maximum static friction is 60 N

(4) Sliding friction is 40 N​

Answer:

(3) The maximum static friction = 60 N.

(4) Sliding friction = 40 N.

Explanation:

Static friction: It is the amount of frictional force required to just keep the body at rest from moving when.

Sliding friction or kinetic friction: The frictional force acting on the body when it is in motion is known as sliding friction.

Coefficient of kinetic friction($\mu_k$) < Coefficient of static friction($\mu_s$)

Now from the given question, when a force of 60 N is applied on the block, and if the block just moves then the maximum static friction = 60 N.

But when the block has just begun to move from rest then the static friction changes to sliding friction and the force required to keep the block in motion is less than the force required to move it from rest.

Therefore, the sliding friction = 40 N.

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