Question

A block of 2 kg is suspended from the ceiling through a massless spring of spring constant K = 100 Newton /metre. what is the elongation of the spring? if another 1 Kg is added to the block what would be the further elongation?

Answer 1

for equilibrium,
mg = -kx
for first case,
2*10= 100*x
x = 5
i
same in second case,
mg = kx'
3*10= 100*( 5+y)
y = 4.7