A block of 20 kg mass is pulled up a slope by applying a force acting parallel to the slope. If the slope makes an angle of 30° with the horizontal, calculate the work done in pulling the load upto a distance of 3 m. (Use g = 10 ms-2. Neglect work done against friction).
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Answer:
here is your answer
Explanation:
1 mass = 20 kg
weight = force = 20*10 = 200N
s = 3m
w.d = fs
= 200*3
= 600 J
potential energy = 600J
2.u= 18km/ hr.= 5 m/ s
v = 9km/ hr. and 2.5 m/ s
w.d = change in kinetic energy= 1/2 m(v²-u²)
= 1/2*70*(2.52-52)
= 35*7.5*-2.5
=656.25 J
change in kinetic energy= 656.25 J (as w.d is a scalar quantity)
initial kinetic energy = 1/2*70*5*5
= 875 J
final kinetic energy = initial kinetic energy - Change in kinetic energy
= 875 - 656.25 J
=218. 75 J
therefore kinetic energy is reduced by one fourth
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