a block of 2kg is given a speed of 6 m/s is stopped by friction in 10sec over a flat surface.The coefficient of friction is
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Hello mate,
mass of the block=2 Kg
initial velocity=6m/s
final velocity=0m/s
and time=10sec
so acceleration of the block=final velocity-initial velocity/time=0-6m/s/10sec=-6/10m/s^2=-0.6 m /s^3
so, force =mass *acceleration=3 kg*-0.6 m/s^2
=-1. 8 Newton
hope helped and plz mark it..
mass of the block=2 Kg
initial velocity=6m/s
final velocity=0m/s
and time=10sec
so acceleration of the block=final velocity-initial velocity/time=0-6m/s/10sec=-6/10m/s^2=-0.6 m /s^3
so, force =mass *acceleration=3 kg*-0.6 m/s^2
=-1. 8 Newton
hope helped and plz mark it..
AbhinavSahni:
plz mark it
but the answer is 0.06
bro but this is looking right
plz mark it
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