Question

a block of aluminium of mass 2 kg was supplied with 3600j of heat. If the sepecfic heat of aluminium is 900j kg-1c-1 then rise in temperature is

Answer 1

answer is

m=2kg

S=900,Q=3600j

Q=msdelta

3600=2×900×delta t

3600=1800 × delta t

delta t= 3600÷1800

delta t =2

delta is represented by small triangle

Answer 2

Answer:

2°C

Explanation:

Q=mst

3600J=2×900×t

3600J=1800×t

3600J/1800=t

2°C