Physics, asked by mithujyothi47, 20 days ago

A block of aluminium of mass 2kg was supplied with 3600J of heat. If the specific heat of aluminium is 900Jkg-1 degree C-1, then the rise in temperature is​

Answers

Answered by Anonymous
0

Answer:

m=2kg

S=900,Q=3600j

Q=msdelta

3600=2×900× t

t= 3600÷1800

t =2

T is represented by small triangle

Explanation:

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