A block of aluminium of mass 2kg was supplied with 3600J of heat. If the specific heat of aluminium is 900Jkg-1 degree C-1, then the rise in temperature is
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Answer:
m=2kg
S=900,Q=3600j
Q=msdelta
3600=2×900× t
t= 3600÷1800
t =2
T is represented by small triangle
Explanation:
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