Question

A block of aluminum of mass 1Kg and volume 3.6 X 10^-4m^3 is suspended from a string and then completely
immersed in a container of water. The decrease in tension in the string after immersion is
(Use g =10 m/s^2)​

Answer 1

Answer:

3.6

Explanation:

when block is in air,tension=weight of block as accelaration is zero.

so tension when block is in air=mg=10N

when immersed in water,

tension=weight of block-buoyant force

buoyant force = volume of substance*density of liquid*acceleration due to gravity

B.F.=3.6/10000*1000*10=3.6N

tension=weight-3.6

tension=10-3.6=6.4N

decrease in tension=10-6.4=3.6N

hope it helps you.