Question

A block of brass has mass 0.5 kg and density 8000 kg/m3.It is suspended from a string . Find the tension in the string if it is completely immersed in water

Answer 1

Answer:

Explanation:

Here observe the diagram and see the answer

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Answer 2

The tension in the string, if it is completely immersed in water, is $\left [ 5 - \frac{5}{8} \right ]$.

Explanation:

Given,

Mass of block = 0.5 kg

Density of block = 8000 kg/m³

We have to find tension in the string.

We know that,

Volume =  $\frac{Mass}{Density}$

Volume of block = $\frac{0.5}{8 \times 10^{3} } m^{3}$

∴ The volume of the block is equal to the volume of water displaced.

Volume of displaced water = $\frac{0.5}{8 \times 10^{3} } m^{3}$

Weight of displaced water = $\frac{0.5}{8 \times 10^{3} } 10^{3} \times 10N$

                                            = $\frac{5}{8}$

This is equal to the upward buoyant force.

Tension in string in actual weight less the upward buoyant force.

Hence, the tension in the string, if it is completely immersed in water, is $\left [ 5 - \frac{5}{8} \right ]$.

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