Question

a block of data is stored in memory location from d001 h 2005 write a program to find the number count number which are divisible by 2 Indian block store result immediately after the end of block​

Answer 1

Answer:

Here is how to find the number count number which are divisible by 2 Indian block store result immediately after the end of block​

Explanation:

Algorithm

Take a count equal to 4

Store the starting address of both blocks in 2 different register pairs

Now exchange the contents at the addresses in both register pairs

Increment the values of both register pairs

Decrements count by 1

If count is not equal to 0 repeat steps 3 to 5

LXI D 2001 – Loads register pair, that is in this case, D=20 and E=01

LXI H 3001 – H=30 and L=01

MVI C 04 – Assigns immediate data, eg.- here C=04

MVI A 45 – assigns A(accumulator) with 45, A=45

MOV B, M – Here M is the data in H – L register pair and it serves as an address. Copies content at address stored in M to register B

LDAX D – Here Accumulator is loaded with the data stored at address formed by register pair D – E

MOV M, A – Here A’s content is copied to address which is stored in M.

MOV A, B – Copies content of register B to A

STAX D – Stores the content of A (accumulator) in the address formed by register pair D – E.

INX H – Increment the content of register pair H – L

INX H – Increment the content of register pair D – E

DCR C – Decrements the content of register C

JNZ 2508 – If value of register C is not equal to 0 then jump to address 2508

HLT – Stop execution of program

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Answer 2

Explanation:

a a block of data store in memory location from :

D-001

H-2005

divisible by 5l