A block of density 2000 kg per metre cube and mass 10 kg is suspended by a spring stiffness hundred newton per metre the other end of the spring is attached to a fixed support the block is completely submerged in a liquid of density 1000 kg per metre cube is the block is in equilibrium position then
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If the block is in equilibrium the the energy stored is 12.5 J
Explanation:
Spring constant "Kx" = V(2000)(10) − V(1000)(10)
= 10 / 2000 [1000 × 10]
Kx=50N ....(1)
U(stored) = 1/2×(100) (50 / 100)^2 = 12×2500 / 100 = 12.5 J
Thus if the block is in equilibrium the the energy stored is 12.5 J
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