Question

A block of density OF 0.o6g/cm3,weighing 3.06N In air,float freely ina liquid of density 0.9g/cm3.calculate the volume of the portion immersed (g=10m/s2

Answer 1

$\rm\small\underline\red{Question:-}$

$\rm\bullet{ \: Density = 0.06 \frac{g}{cm} ^{(3)} }$

$\rm\bullet{ \: Air= 3.06 \: N}$

$\rm\bullet{ \: Liquid \: density = 0.9\frac{g}{cm} ^{(3)} }$

$\rm\small\underline\red{ \: Find:-}$

• calculate the volume of the portion immersed.

$\rm\small\underline\red{Solution:-}$

$\rightarrow\rm\small\green{ F = mg }$

$\rightarrow \rm \small{3.06 = 3 \times 10}$

$\rm\rightarrow{m = \frac{3.06}{1000} \: g m}$

$\rightarrow\rm\small{Volume = \frac {3.06}{1000 } {(0.9)} \: }$

$\rm\rightarrow \: \frac{306 \times\cancel {10} }{ \cancel{1000} \times 9}$

$\rightarrow\rm \small\frac{\cancel{30}}{ \cancel{900}}$

$\dashrightarrow\rm\small\fbox\green{ Volume = 3 m }$

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