A block of dimension (0.6 by 0.3 by 0.2)m has force of 600N. Calculate its maximum and minimum pressure
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Answer:
a. F
fric
=μ
s
W=0.4∗20=8N
b. Since F
applied
<F
fric
F
fric
=5N
c. Minimum force required to start the motion F=F
staticfric
=8N
d. Minimum force required to start the motion
F=F
kineticfric
=μ
k
W=0.2∗20=4N
e. F>F
staticfric
motion started.
F>F
kineticfric
hence motion continues.
F
fric
=4N
Explanation:
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