a block of glass is kept on a wooden board the mass of the glass block is 2kg and its dimension are 8cm,5cm,1cm,find the pressure exerted by the glass block on wooden board if its made to lie on the board with dimensions
5cmm,1cm
8cm,5cm
Answers
Answered by
14
Case 1 : 5cm × 1cm
Pressure= Force /Area
= 2(10) / 5×1
= 20/5 = 4 N/cm²
Case 2 : 8cm × 5cm
P = F/A
= 2(10)/8×5
= 20/40 = 0.5 N/m²
Pressure= Force /Area
= 2(10) / 5×1
= 20/5 = 4 N/cm²
Case 2 : 8cm × 5cm
P = F/A
= 2(10)/8×5
= 20/40 = 0.5 N/m²
Divyankasc:
In case 2, at last it's N/cm² not N/m²
Answered by
9
hi there,
1.p=f/a
f=ma=2*10=20 (g=10)
area=5
pressure=20/5=4Pa
2.area=40
pressure=20/40=1/2=.5 N/cm^2
i hope this helps u nd pls smash th ethanks button
1.p=f/a
f=ma=2*10=20 (g=10)
area=5
pressure=20/5=4Pa
2.area=40
pressure=20/40=1/2=.5 N/cm^2
i hope this helps u nd pls smash th ethanks button
thanks mate
Hey! Pascal is N/m² here its cm²
thanx
correct urs too
Mine was already correct ^_^
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