Question

A block of ice of 10 gmat - 10°C is slowly heated and converted to steam at 100°C, calculate the amount of heat required to change ice at -10°C to steam at 100°C. (specific heat of ice is 0.5 cal/gmºC and latent heat of ice 80 cal/gm and latent heat of vaporization of water is 540 cal/gm and Sw= 1 cal/gm/°C]
a) 7250 cal
b) 2750 cal
c) 5720 cal
d) none of these​

Answer 1

Answer:

Option-a

Explanation:

Q=Ms(t2-t1) apply for ice this gives the amount of heat required to convert ice at -10 to 0 celcius that will be 50cal.

now ice came to o celcius but it will be in solid state only . now apply latent heat of fusion that will be 800calfor 10 gm.now apply q=Ms( t2-t1) for water at o to 100 celcius that will be 1000.now water will transfer from liquid state to stem.then apply latent heat of vaporisation that will be 5400