Question

A block of ice of density 0.9 gm cc-¹and of volume 100 cc floats in water. Then volume of ice inside the water.
a) 10 cc
b) 90 cc
c) 50 cc
d) 9 cc​

Answer 1

Answer:

90 cc

Explanation:

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Answer 2

Given:-

→ Density of the block of ice = 0.9 g/cc

→ Volume of the block of ice = 100 cc

To find:-

→ Volume of ice inside water

Solution:-

As the block of ice is floating in water, so according to Laws of floatation :-

Weight = Buoyant force

(Volume of body) × (density of body) = (Volume of liquid displaced) × (density of liquid)

=> V₁ × ρ₁ = V₂ × ρ₂

=> ρ₁/ρ₂ = V₁/V₂

= Vol.of liquid displaced/Vol.of body

= Vol. of body in liquid/Vol.of body

=> V₂ = ρ₁V₁/ρ₂

Where :-

• V₂ is the volume of body in liquid.

• ρ₁ is the density of the body.

• V₁ is the volume of body.

• ρ₂ is the density of the fluid.

Density of water is 1g/cc. So by substituting values, we get :-

=> V₂ = 100×0.9/1

=> V₂ = 90 cc

Thus, volume of ice inside water is 90cc [Option.b]