Question

a block of iron floats on Mercury find the fraction of volume which remains immersed in Mercury densities of Mercury and iron are 13.6 and 7.8 gram per centimetre cube respectively​

Answer 1

Answer:

Explanation:

Let V be the volume of the iron body and ν be its volume immersed in mercury.

For floatation Weight of the body = Weight of the liquid displaced by the immersed portion of the body.

i.e., V × 7.8 × g = ν × 13.6 × g

or ν/V = 7.8/13.6

= 0.574

or ν = 0.574 V

The fraction 0.574 of total volume will remain immersed.

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