A block of iron has dimensions 2 m X 0.5 m X 0.25m.The density of iron is 7.8 g cm–³ . Find the mass of block.
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Answer:
Given , I = 2m
b = 0.5m
h= 0.25m
Density of iron = 7.8gcm3 = 7.8×1000kgm−3 = 7800kgm−3
Volume of block = l×b×h
= 2×0.5×0.25 = 0.25m3
From relation d= VM
∴ Mass of iron block M=V×d
= 0.25×7800kgm3
= 1950kg
Explanation:
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