Question

A block of iron has dimensions 2cmx 0.5cmx0.25 cm. The density of iron is 7.8 g/cm^3. Find its mass in gram. *

Answer 1

Explanation:

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A block of iron has dimensions 2m×0.5m×0.25m. The density of iron is 7.8gcm

−3

Find the mass of block.

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Answer

Given , I = 2m

b = 0.5m

h= 0.25m

Density of iron = 7.8gcm

3

= 7.8×1000kgm

−3

= 7800kgm

−3

Volume of block = l×b×h

= 2×0.5×0.25 = 0.25m

3

From relation d=

V

M

∴ Mass of iron block M=V×d

= 0.25×7800kgm

3

= 1950kg

Answer 2

Answer:

Given , I = 2cm

Given , I = 2cmb = 0.5cm

Given , I = 2cmb = 0.5cm h= 0.25mcm

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d=

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d= V

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d= VM

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d= VM

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d= VM

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d= VM ∴ Mass of iron block M=V×d

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d= VM ∴ Mass of iron block M=V×d= 0.25×7800kgm

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d= VM ∴ Mass of iron block M=V×d= 0.25×7800kgm 3

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d= VM ∴ Mass of iron block M=V×d= 0.25×7800kgm 3

Given , I = 2cmb = 0.5cm h= 0.25mcmDensity of iron = 7.8gcm 3 = 7.8×1000kgm −3 = 7800kgm −3 Volume of block = l×b×h= 2×0.5×0.25 = 0.25cm3 From relation d= VM ∴ Mass of iron block M=V×d= 0.25×7800kgm 3 = 1950kg

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