Question

a block of iron has dimensions 2m * 0.5m*0.23m . the density of iron is 7.8 g/cm^3 . Find the mass of the block​

Answer 1

density, d = 7.8g/cm^3 = 7800 kg/m^3

Volume , v= 2 x 0.5 x 0.23 = 0.23 m^3

mass m =?

d= m/v

⇨m = d x v

= 7800 x 0.23

= 1794 kg

Answer 2

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Volume of the iron dimensions is 2 * 0.5*0.23 = 0.23 m^3.

Density = 7.8 g/cm^3*1000 = 7800 kg/m^3.

Mass = Density / volume,

= 7800/0.23,

Mass = 33391.04 kg

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