Question

A block of iron of mass 7.5 kg and of dimension 12cm× 10cm × 8cm is kept on a table top on its base of side 12cm × 8cm. calculate thrust
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Answer 1

Mass of Iron block (m) = 7.5 kg

Dimensions of the base of Iron block = 12 cm × 8 cm

So , Area of the block (A) = 96 cm²

⇒ A = 96 × 10⁻⁴ m²

Thrust (P) : It is defined as force acting per unit area

Here force acting is given by the weight of the object .

$\to \sf P=\dfrac{F}{A}\\\\\to \sf P=\dfrac{Weight}{A}\\\\\to \sf P=\dfrac{mg}{A}\\\\\to \sf P=\dfrac{(7.5)(10)}{96\times 10^{-4}}\\\\\leadsto \sf \pink{P=7812.5\ Pa}\ \; \bigstar$

Thrust = 7812.5 Pa

More Info :

SI unit of Pressure is Pascal

SI unit of Force is Newton