Question

A block of iron of mass 7.5 kg and of dimensions 12 cm * 8 cm * 10 cm is kept on a table top on its base of side 12 cm * 8 cm. Calculate : (a) thrust and (b) pressure exerted on the table top. Take 1 kgf = 10 N. [Ans.] (a) 75 N (b) 7812.5 Pa

Answer 1

Given: A block of iron of mass 7.5 kg and dimensions 12 cm x 8 cm x 10 cm

To find: (a) thrust and (b) pressure exerted on the table top

Solution:

• Now we have given the mass of the iron block as 7.5 kg.

• Now we know that Thrust = Force

• We also know that force = mg, so:

                thrust = mg

                thrust = 7.5 × 10

                thrust = 75 N

• Now we have given the dimensions as  12 cm x 8 cm x 10 cm.

• Area of the surface of iron block kept on the table

                = 12 × 8 = 96 cm²

                = 0.0096 m²

• Now we know the formula:

                Pressure = Thrust / Area

                Putting values in it, we get:

                Pressure = 75 / 0.0096

                Pressure = 7812.5 Pa

Answer:

            So the thrust is 75 N and pressure is 7812.5 Pa.

Answer 2

Answer:

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