Question

A block of iron of mass 7.5 kg and of dimensions
12 cm x 8 cm x 10 cm is kept on a table top on its
base of side 12 cm x 8 cm. Calculate : (a) thrust
and (b) pressure exerted on the table top. Take 1kgf =10N​

Answer 1

Answer:

Thrust = mg=7.5×10=75N

Pressure =

A

F

=

10×10

−2

×8×10

−2

75

=0.78125×10

4

=7812.5Pa

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Answer 2

Explanation:

mass of the iron block as 7.5 kg.

Thrust = Force

force = mg, so:

              thrust = mg

               thrust = 7.5 × 10

              thrust = 75N

dimensions :  12 cm x 8 cm x 10 cm.

Area of the surface of iron block kept on the table

               = 12 × 8 = 96 cm²

               = 0.0096 m²

               Pressure = Thrust / Area

               Pressure = 75 / 0.0096

               Pressure = 7812.5 Pa

Answer:  thrust is 75 N and pressure is 7812.5 Pa.