Question

A block of iron of mass 7.5 kg and of dimensions 12cm×8cm×10cm is kept on a table top on its base of side 12cm×8cm. Calculate:
thrust
pressure exerted on table top
[Take 1 kgf=10 N]

Answer 1

Answer:

7812.5 Pa

Explanation:

Pressure = Force/ area

=(7.5 ×10)/ (0.12×0.08)

=75/(0.0096)

=7812.5 Pa

Answer 2

$\bold{(a) \: thrust}$

$\bold{Force \: = \: Mass \: × \: acceleration \: due \: to \: gravity} \\ \bold{ = \: 7.5 \times 10} \\ \bold{ = 75N \: .... \: \: ans}$

$\bold{(b) \: pressure \: exerted \: on \: tabletop}$

$\bold{Area \: of \: the \: tabletop \: = \: 12 × 8} \\ \bold{ \: \: \: = 96 {cm}^{2} \: to \: {m}^{2} } \\ \bold{ \: \: \: = \: \frac{96}{1000} {m}^{2} } \\ \bold{ \: \: \: = \: 0.0096 {m}^{2} }$

$\bold{Therefore,}$

$\bold{Pressure \: = \: \frac{force}{area} } \\ \bold{ \: \: \: \: \: \: \: \: = \: \frac{75}{0.0096} } \\ \bold{ \: \: \: \: \: = \: \frac{75 \times 10000}{96} } \\ \bold{ \: \: \: \: \: = \:\frac{ \cancel{75} \: \: \: ²⁵ \times \cancel{10000} \: \: ⁶²⁵}{ \cancel{96} \: \: ²} } \\ \bold{ \: \: \: = \: \frac{25 \times 625}{2} } \\ \bold \red{ \: \: \: = \: 7182.5 \: Pa \: \: ....ans}$

hope it helps you...

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