Question

A block of mass 0.1 KG is attached to a spring and placed on a horizontal frictionless table. The spring is stretched 20cm when a force of 5N is applied. Calculate the spring constant.

Answer 1

Answer:

Answer: The spring constant of the spring is 25 N/m.

Answer 2

Answer:

F = kx

K = 5/0.2 = 50/2 = 25N/M

T = 2π✓m/K

T = 2×3.142✓0.1/25

T = 6.284×0.0632

T = 0.397Sec

Explanation:

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