Question

A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is?

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Answer 1

Answer:

0.98

Explanation:

f max=force applied*coefficient of friction

=5*0.5

=2.5

here f max is greater than mg

so we consider mg as friction since static friction is self adjusting

mg=0.1*9.8

=0.98

Answer 2

Answer:

f=u*n

where f is limiting friction and u=0.5

and n is normal reaction

f=0.5*5

=2.5N

Now,

f=mg

=0.1*9.8

=0.98N

therefore frictional force is 0.98N

hope it helps yrr