A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the mass is 0.5, find the magnitude of the frictional force acting on the block?
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Limiting frictional force, fl=μsN=0.5×5=2.5N. tending to produce relative motion is the weight (W) of the block which is less than fl. Therefore, the frictional force is equal to the weight, the magnitude of the frictional force f has to balance the weight 0.98 N acting downwards. Therefore the frictional force =0.98N
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Answer:
Limiting frictional force, fl=μsN=0.5×5=2.5N. tending to produce relative motion is the weight (W) of the block which is less than fl. Therefore, the frictional force is equal to the weight, the magnitude of the frictional force f has to balance the weight 0.98 N acting downwards. Therefore the frictional force =0.98N.06
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