Question

a block of mass 0.1 kg is held against a well by applying a horizontal force of 5 N on the block if the cofficient friction b/w the block and the well is 0.5 the magnitude of the friction force acting on the block is

Answer 1

hi,

mass of block = 0.1kg

horizontal force(N) =5N

u = 0.5

frictional force = uN

= ( 0.5 ) ( 5 )

= 2.5

therefore the applied force is more than maximum frictional force

so the body is in equillibrium

i.e., Weight (W) = Mg

= ( 0.1 )( 9.8 )

= 0.98

frictional force is equal to weight

which is approximately equal to 1

hope it helps...❤

Answer 2

Explanation:

here is answer

hope help you

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