Question

a block of mass 0.18 kg is attached to a spring of force constant 2 n/m. the coefficient of friction between the block and the floor is 0.1. initially the block is at rest and the spring is un-stretched. an impulse is given to the block as shown in the figure. the block slides a distance if 0.06 m and comes to rest for the first time. the initial velocity of the block in m/s is v = n/10. then n is​

Answer 1

Answer:

it will be in newton

Explanation:

please draw the FBD of the block.....from there u will find the eqilibrium condition,friction coefficient is given,initial velocity is zero put that in impulse momentum theorem.....and the final velacity put it in equilibrium condition from there u will get N....take the hint and rock....

Answer 2

It'll be in newton.....

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