Question

A block of mass 1 kg attached to a light string
and whirled around in a horizontal circle of
radius 1 m with angular velocity 10 rad/s. Find
minimum tension in string so that string does not
break.
(a) 50 N (b) 100 N (c) 200 N (d) 500 N​

Answer 1

The tension in string shud be equal to the centripetal force

T = mw²r

T = 1*(10)² *1

T = 100 N

Answer 2

Answer:

100N

Explanation:

As we know the formula of centripetal force,

As we know the formula of centripetal force,T=(mv^2)/r

As we know the formula of centripetal force,T=(mv^2)/rT= 1×100/1

As we know the formula of centripetal force,T=(mv^2)/rT= 1×100/1T=100N