Question

A block of mass 1 kg is horizontally thrown with velocity of 10 m/s on a stationary long rough plank whose coefficient of kinetic friction is 0.25. After what time block will come to rest?​

Answer 1

Answer:

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Explanation:

Consider the common velocity of the system= V

By conservation of Momentum:-

1×10=(2+1)V

So, V=10/3

Force on block= μmg=5×1×10=5N

De-acceleration of block a= 5a/1=5m/s

2

Let time to change the velocity from 10 to 10/3 is t then,

10−10/3=at=5t

or, t=

5×3

20

=

3

4

s

Even at sliding condition, limiting friction is acting.