Question

A block of mass 1 KG is kept idly on a floor. What is the frictional force being acted on the block. (take g=10)

Answer 1

Answer- The above question is from the chapter 'Laws of Motion'.

Given question: A block of mass 1 Kg is kept idly on a floor. What is the frictional force being acted on the block? (Take g = 10 m/s²)

Answer: A block of mass 1 Kg is kept idly on a floor.

Mass of block (m) = 1 Kg

Acceleration due to gravity (g) = 10 m/s²

Forces acting on the block are:

1) Weight due to gravitational pull (mg)

2) Normal force (N)

3) Frictional force ($f_{l}$)

The equations of motion are:

N - mg = 0

N = mg

N = 1 × 10 = 10 N

Limiting friction ($f_{l}$) = μ × N

where μ = coefficient of static friction (not given)

$f_{l}$ = μ × N

$f_{l}$ = μ × 10

∴ Frictional force = 10  μ Newton