Question

A block of mass 1 kg is placed on a rough surface with coefficient of friction mu = 0.2 A force, whose magnitude varies linearly with time, starts acting onthe block. The force starts increasing from zero at the rate of 0.2N / s . Thetime after which the block attains a velocity of 10 m/s is (g = 10 m/s ^ 2)​

Answer 1

Answer:

0

Explanation:

From the given figure we get

f=⎩⎪⎪⎨⎪⎪⎧2tt<12(t−1)1<t<22(t−2)2<t<3Now,Netforceonblockma=F−μgma=mF−μga=⎩⎪⎪⎨⎪⎪⎧2tt<12(t−1)1<t<22(t−2)2<t<3Then∫2vdtdv=∫012(t−1)dt+∫122(t−2)dt+∫232(t−3)dtv−2=∫01t2−2t+∫12(t2−4t)+