A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 30∘ by a force of 10 N parallel to the inclined surface as shown in the figure. The coefficient of friction between block and the inclines is 0.1. If the block is pushed up by 10 m along the incline, then the work done against energy of friction is??
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The various forces acting on the block are as shown in the figure.
Here, m=1 kg,θ=30∘,F=10 N
μ=0.1,d=10 m
Work done against gravity is
Wg=mgdsinθ
=(1 kg)×(10 ms−2)×10×sin30∘m=50 J.
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