A block of mass 1 kg is released from rest at t=0 to fall freely under gravity. find the power of gravitational force acting on it at t = 2 sec. (g = 10m/s^2)
Answers
Answered by
0
m=1kg
power = work /time
force *mass
Ma *m
a=g
1*10*1/2
10/2=5
power = work /time
force *mass
Ma *m
a=g
1*10*1/2
10/2=5
rohit9548:
hello sister
hlw
how are you?
Similar questions