A block of mass 1 kg is resting on a rough
horizontal surface with coefficient of friction 0.2. If an
impulse (10i 10j) Ns is given to block by
hammering i
the velocity of block just after the
given impulse is
Ly-axis
is along verticall
10 Ns
10 Ns
u x
0.2
(1) 10 m/s
(2) 0 m/s
(4) 4 m/s
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Impluse (I) = p(f) - p(i)
p(i) = 0
p(f) - p(i) = mv
The velocity of the block just after the given impluse (10 i, 10 j) is :-
velocity (v) = I (impluse) / m (mass)
velocity (v) = 10 NS / 1 kg
v = 10 m/s
p(i) = 0
p(f) - p(i) = mv
The velocity of the block just after the given impluse (10 i, 10 j) is :-
velocity (v) = I (impluse) / m (mass)
velocity (v) = 10 NS / 1 kg
v = 10 m/s
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