Question

A block of mass 1 kg just remain in equilibrium with the vertical wall of cart accelerating uniformly with 20 m per second square as show the coefficient of friction between block and wall is​

Answer 1

Answer:

The coefficient of friction between block and wall is​ 0.5

Explanation:

According to the problem the mass of the block is m= 1 kg

The acceleration of the cart is a= 20 m/s^2

In this problem a force is working on the opposite direction of the acceleration

let the force be f = mg

Therefore from newton's 2nd law,

N = ma

let the coefficient friction of block be μ

now the frictional force will be,

f = μN

mg = μ x ma

g = μ a

μ = g/a

if we assume g = 10 m/s^2

therefore μ = 10 /20

μ = 0.5

Answer 2

μ=0.5

hope it will help you