A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m//s^2, the frictional force acting on the block is…………newtons.
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Maximum frictional force acting =μmg=0.6×1×10=6N
Pseudo force acting on the body =ma=1×5=5N
∵ pseudo force < frictional force
The frictional force acting is only 5N.
Explanation:
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