Question

a block of mass 1 kg lies on a horizontal surface in a truck. the coefficient of static friction between the block and the surface is if the acceleration of the truck is 5 metre per -2 square calculate the frictional force acting on the block.​

Answer 1

Answer:

$limiting \: \: friction \\ f = u \\ mg = 0.6 \times 1 \times 9.8 = 588n \\ applied \: \: force \\ f = ma = 1 \times 5 \\ = 5n \\ as \: \: f < f \\ so \: \: \: force \: \: of \: \: friction = 5n.$

Answer 2

Answer:

Maximum frictional force acting =μmg=0.6×1×10=6N

Pseudo force acting on the body =ma=1×5=5N

∵ pseudo force < frictional force

The frictional force acting is only 5N.